ZK协处理器如何打破智能合约数据壁垒
币界网报道:```python
def my_function(x):
if x <= 1:
return "less than or equal to one"
elif (2/x).is_integer():
# If the fraction is an integer, we can use int() instead of round() and it's faster!
result = math.floor(int(3*x)/4+0.5)*1j ### This line needs improvement too ###
else:
return "greater than one"
```
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